Calorimetry Lab
1. Of the food items we will be testing (large marshmallows, regular cheetos, flaming hot cheetos), hypothesize which one will have the most calories and which will have the least. Why to you this this to be the case?
I think that the large marshmallow will have the most calories. I think that its large that the average cheeto and so much of it is made of sugar and chemicals to hold it together that will result in a lot of calories. I think that the hot cheetos will have the least calories because I think that the regular cheetos will have more calories than it. The regular cheetos have “cheese” in them which is a fatty food. The hot cheetos don’t have that much cheese on them.
2. Rank those three food items according to energy content from highest to lowest. Why did you place them in that order?
Marshmallow, regular cheetos, hot cheetos. I think that the energy level may be the same as the calorie level. When I think of energy and calories, I think that if you eat a lot of calories you need to burn off. I imagine like the calories are stored energy that you need to burn off. I think of athletes who eat a ton and a ton, but then go and burn it off and it gives them energy. Marshmallows contain a lot of sugar and since sugar is in a lot of energy drinks I ranked it as having the most energy.
3. Define the term “specific heat”.
The heat needed to make the temperature of the unit mass of a given substance by a given amount (usually one degree) rise.
4. What is specific heat of water?
1 calorie/gram °C = 4.186 joule/gram °C
5. What is the specific heat of air?
1.01 joule/gram C 0.24 calorie/gram C
6. What is the difference in chemistry between a calorie and a Calorie?
1 calorie = 1000 Calorie
7. Define the terms in the following equation: Q=m*c*∆T.
Q= heat added, c= specific heat, m= mass, ∆T= change in temperature.
Mass of Can (g) Mass of Can + H20 (g) Mass of H20
14 g 64.1 g 50 g
14.1 g 64.1 g 50 g
14.1 g
64.4 g 50.3 g
15.6 g
65.8 g 50.2 g
13.9 g 63.8 g 49.9 g
14.3 g 64.3 g 50 g
Food Sample Initial Mass Final Mass ∆ Mass of Food (g) Initial Temp (ºC) ∆ Temp (ºC) Final Temp (ºC)
Marshmallow 11.9 g 11.1 g 0.8 g 20ºC 4ºC 24ºC
2 Marshmallow 10.6 g 10.6 g 0 g No change 21ºC 4ºC 25ºC
Regular Cheeto 4.7 g 4.7 g 0 g No change 21ºC 6ºC27ºC
2 Regular Cheeto 4.6 g 4.1 g 0.5 g 22ºC 10ºC 32ºC
Hot Cheeto 4.2 g 4.1 g 0.1 g 23ºC 2ºC 25ºC
2 Hot Cheeto 4.4 g 3.8 g 0.6 g 22ºC 9ºC 31ºC
Post Lab Questions
1. Calculate how many calories were transferred to the water by the marshmallows.
Calories= grams of water * (final ºC - initial ºC)
Calories= 50 g * (24ºC-20ºC)
Calories= 50 g * 4ºC
Calories= 200
2. Divide this number of calories by the grams of marshmallows that burned up to give you the number of calories per gram in a marshmallow.
Calories= 200 divide by 0.8g
Calories/gram= 200/0.8
Calories/gram= 250
3. Marshmallows actually contain about 3.33 calories per gram. Based on this, calculate what percent of the heat you lost to the air around the calorimeter.
heat lost:
250/3.33=x/100
250*100= 25000
3.33*x= 3.33x
25000/3.33=7507
7507% of heat was lost to the air.
4. Repeat steps 1 through 3 for a cheeto. Solve the ratio below to figure out the actual calories per gram in a Cheeto.
calculated/(100-% lost) = actual/100
Calories= grams of water * (final ºC - initial ºC)
Calories= 50g * (32ºC-22ºC)
calories= 50g * (10ºC)
Calories= 500
500/100-11%= x/100
500/89= x/100
500*100=89x
50,000/x=89/x
x=562 cal/gram
actual = 565 cal/gram
5. How close does your answer for #4 come to real value for Cheetos (6 calories/grams)?
It is actually very close.
The answer I calculated above was 562 calories/gram for Cheetos. The actual amount that I looked up was 565 calories/gram. I was just 3 calories off, I was very close.
I think that the large marshmallow will have the most calories. I think that its large that the average cheeto and so much of it is made of sugar and chemicals to hold it together that will result in a lot of calories. I think that the hot cheetos will have the least calories because I think that the regular cheetos will have more calories than it. The regular cheetos have “cheese” in them which is a fatty food. The hot cheetos don’t have that much cheese on them.
2. Rank those three food items according to energy content from highest to lowest. Why did you place them in that order?
Marshmallow, regular cheetos, hot cheetos. I think that the energy level may be the same as the calorie level. When I think of energy and calories, I think that if you eat a lot of calories you need to burn off. I imagine like the calories are stored energy that you need to burn off. I think of athletes who eat a ton and a ton, but then go and burn it off and it gives them energy. Marshmallows contain a lot of sugar and since sugar is in a lot of energy drinks I ranked it as having the most energy.
3. Define the term “specific heat”.
The heat needed to make the temperature of the unit mass of a given substance by a given amount (usually one degree) rise.
4. What is specific heat of water?
1 calorie/gram °C = 4.186 joule/gram °C
5. What is the specific heat of air?
1.01 joule/gram C 0.24 calorie/gram C
6. What is the difference in chemistry between a calorie and a Calorie?
1 calorie = 1000 Calorie
7. Define the terms in the following equation: Q=m*c*∆T.
Q= heat added, c= specific heat, m= mass, ∆T= change in temperature.
Mass of Can (g) Mass of Can + H20 (g) Mass of H20
14 g 64.1 g 50 g
14.1 g 64.1 g 50 g
14.1 g
64.4 g 50.3 g
15.6 g
65.8 g 50.2 g
13.9 g 63.8 g 49.9 g
14.3 g 64.3 g 50 g
Food Sample Initial Mass Final Mass ∆ Mass of Food (g) Initial Temp (ºC) ∆ Temp (ºC) Final Temp (ºC)
Marshmallow 11.9 g 11.1 g 0.8 g 20ºC 4ºC 24ºC
2 Marshmallow 10.6 g 10.6 g 0 g No change 21ºC 4ºC 25ºC
Regular Cheeto 4.7 g 4.7 g 0 g No change 21ºC 6ºC27ºC
2 Regular Cheeto 4.6 g 4.1 g 0.5 g 22ºC 10ºC 32ºC
Hot Cheeto 4.2 g 4.1 g 0.1 g 23ºC 2ºC 25ºC
2 Hot Cheeto 4.4 g 3.8 g 0.6 g 22ºC 9ºC 31ºC
Post Lab Questions
1. Calculate how many calories were transferred to the water by the marshmallows.
Calories= grams of water * (final ºC - initial ºC)
Calories= 50 g * (24ºC-20ºC)
Calories= 50 g * 4ºC
Calories= 200
2. Divide this number of calories by the grams of marshmallows that burned up to give you the number of calories per gram in a marshmallow.
Calories= 200 divide by 0.8g
Calories/gram= 200/0.8
Calories/gram= 250
3. Marshmallows actually contain about 3.33 calories per gram. Based on this, calculate what percent of the heat you lost to the air around the calorimeter.
heat lost:
250/3.33=x/100
250*100= 25000
3.33*x= 3.33x
25000/3.33=7507
7507% of heat was lost to the air.
4. Repeat steps 1 through 3 for a cheeto. Solve the ratio below to figure out the actual calories per gram in a Cheeto.
calculated/(100-% lost) = actual/100
Calories= grams of water * (final ºC - initial ºC)
Calories= 50g * (32ºC-22ºC)
calories= 50g * (10ºC)
Calories= 500
500/100-11%= x/100
500/89= x/100
500*100=89x
50,000/x=89/x
x=562 cal/gram
actual = 565 cal/gram
5. How close does your answer for #4 come to real value for Cheetos (6 calories/grams)?
It is actually very close.
The answer I calculated above was 562 calories/gram for Cheetos. The actual amount that I looked up was 565 calories/gram. I was just 3 calories off, I was very close.